بررسی بخش پذیری دو عدد

def my_number(x,y):
    result = x % y
    if result == 0:
        print(x,'bar',y,'baksh pazir ast')
    else:
        print(x,'bar',y,'baksh pazir nist')
        #ba "eval" mishe add float ham estefade kard
x = eval(input('enter number1:'))
y = eval(input('enter number2:'))
my_number(x,y)

Alirezaakbari

A

دانلود Python

adad_1 = int(input('adade aval : '))
adad_2 = int(input('adade dovom : '))
if adad_1 % adad_2 == 0:
    print ('bakhsh pazir')
else:
    print ('bakhs pazir nist')

کاربر 2515

2

دانلود Python

a=int(input("a="))
b=int(input("b="))
if int(a%b==0):
    print("a bar b bakhsh pazir ast")
else :print("a bar b bakhsh pazir nist")

Mohsen0safari

M

دانلود Python

number1=int(input("please enter number1: "))
number2=int(input("please enter number2: "))
if number1%number2==0 or number2%number1==0:
    print("yes")
else:
    print("no")    

کاربر 2044

2

دانلود Python

def bakhshpaziri(a,b):
    c=a%b
    if c==0:
        return(c,"bakhshpazir ast")
    else:
        return("bakhshpazir nist")
a=int(input("insert num1...>"))
b=int(input("insert num2...>"))
print(bakhshpaziri(a,b))

Mary12

M

دانلود Python

while True:
    a=int(input('insert num1...>'))
    b=int(input('insert num2...>'))
    if a%b==0:
        print(True)
        print('A bar B bakhshpazir ast.')
    else:
        print(False)
        if a==0:
            break
            

Mary12

M

دانلود Python

number1 = int(input("Enter first number: "))
number2 = int(input("Enter second number: "))
if number1 % number2 == 0:
    print(f"{number1} is divisible by {number2}")
else:
    print(f"{number1} is not divisible by {number2}")

Mohsenakbarpour

M

دانلود Python